how to proceed after clicking a link to new page in selenium in python

Question

I am clicking a link which takes me to new page, but I don't know how to proceed after that. When I try to find an element by id in the next page it gives me error:

selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: {"method":"id","selector":"myid"} 

My code:

browser = webdriver.Firefox()

browser.get('myurl')
elem = browser.find_element_by_id('closeMessageButton') # Find the search box
elem.click() # this takes me to new link

# now I am searching id from new page
elem = browser.find_element_by_id('newpage_id')  #
elem.click()

I have seen this http://www.obeythetestinggoat.com/how-to-get-selenium-to-wait-for-page-load-after-a-click.html but couldn't succeed in implementing for my case. I think the information in browser is not updated yet.

Answer 1

The problem is that you don't switch to opened window, and webdriver searches for elements in the old page instead of the newly opened one.

Solution:

String winHandleBefore = driver.getWindowHandle();
        for(String winHandle : driver.getWindowHandles()){
            driver.switchTo().window(winHandle);
        }

This java method's part switches to the newest window. Also consider maximizing it, because sometimes tests masses up in not maximized windows. Another point: waiting. Try to read here about different types of wait. Good luck.

Answer 2

Solution for Python. This code will switch to the second window in your browser.

window_after = driver.window_handles[1]
driver.switch_to.window(window_after)

Answer 3

After navigating to the new page if you want to do something on that new page

newURl = driver.window_handles[0]

driver.switch_to.window(newURl)

After doing this you can do something in the new url without getting "no such element exceptions"