Click on field in new window

Question

In selenium webdriver, I am trying to click on a field in new window, but I keep getting error as

 "Timed out after 20 seconds waiting for presence of element located by: By.xpath: .//*[@id='UpdatePanel1']/table/tbody/tr[2]/td/table/tbody/tr[1]/td Build info: version: '2.48.2', revision: '41bccdd', time: '2015-10-09 19:55"

Here's the piece of code I have written. Kindly help

public class AE_Shipment {

public void AE_Shipment1() throws InterruptedException 
{
    MyClass1 M1= new MyClass1();
    WebDriver w1 = M1.w;
    w1.findElement(By.xpath(".//*[@id='MainMenu-mI001']")).click();
    w1.findElement(By.xpath(".//*[@id='MainMenu-mI001-sM-mI001']/table/tbody/tr/td[2]")).click();
    w1.findElement(By.xpath(".//*[@id='MainMenu-mI001-sM-mI001-sM-mI000']/table/tbody/tr/td[2]")).click();
    w1.findElement(By.xpath(".//*[@id='MainMenu-mI001-sM-mI001-sM-mI000-sM-mI000']/table/tbody/tr/td[2]")).click();

    WebDriverWait wait = new WebDriverWait(w1, 20);
    wait.until(ExpectedConditions.presenceOfElementLocated(By.xpath(".//*[@id='UpdatePanel1']/table/tbody/tr[2]/td/table/tbody/tr[1]/td")));

    w1.findElement(By.id("ButSearch")).click();
}

Update: I have tried switching to the new window using the code below but I get the same error.

String parentHandle = w1.getWindowHandle(); // get the current window handle 
w1.findElement(By.xpath(".//*[@id='ButSearch']")).click(); 
for (String winHandle : w1.getWindowHandles()) 
{ 
    w1.switchTo().window(winHandle); // switch focus of WebDriver to the next found window handle (that's your newly opened window) 
}

Answer 1

We have to use SwitchTo() functions, to click an element on new window which opens from your original webDriver instance. Following code might work.

public class AE_Shipment {

public void AE_Shipment1() throws InterruptedException 
{
    MyClass1 M1= new MyClass1();
    WebDriver w1 = M1.w;

 // get the current window handle
 String patentWindow = w1.getWindowHandle();

    w1.findElement(By.xpath(".//*[@id='MainMenu-mI001']")).click();
    w1.findElement(By.xpath(".//*[@id='MainMenu-mI001-sM-mI001']/table/tbody/tr/td[2]")).click();
    w1.findElement(By.xpath(".//*[@id='MainMenu-mI001-sM-mI001-sM-mI000']/table/tbody/tr/td[2]")).click();
    w1.findElement(By.xpath(".//*[@id='MainMenu-mI001-sM-mI001-sM-mI000-sM-mI000']/table/tbody/tr/td[2]")).click();

 // switch focus of WebDriver to the next found window handle (that's your newly opened window)
 for (String newWindow : w1.getWindowHandles()) {
  w1.switchTo().window(newWindow); 
 }

    WebDriverWait wait = new WebDriverWait(w1, 20);
    wait.until(ExpectedConditions.presenceOfElementLocated(By.xpath(".//*[@id='UpdatePanel1']/table/tbody/tr[2]/td/table/tbody/tr[1]/td")));

 // click the element on new window
    w1.findElement(By.id("ButSearch")).click();

 // close newly opened window when done with it. (If required)
 w1.close(); 

 // switch back to the original window
 w1.switchTo().window(patentWindow); 
}

Answer 2

There is something wrong with the way you have mentioned your code.

You've mentioned that your element is in new window-I am assuming the waiting needs to be done once you have switched the window.

So you need to place the wait condition after your window handling code-

String parentHandle = w1.getWindowHandle(); // get the current window handle 
w1.findElement(By.xpath(".//*[@id='ButSearch']")).click(); 
for (String winHandle : w1.getWindowHandles()) 
{ 

 w1.switchTo().window(winHandle); // switch focus of WebDriver to the next found window handle (that's your newly opened window) 

    WebDriverWait wait = new WebDriverWait(w1, 20);
wait.until(ExpectedConditions.presenceOfElementLocated(By.xpath(".//*[@id='UpdatePanel1']/table/tbody/tr[2]/td/table/tbody/tr[1]/td")));

//do whatever you want to do here
}

This should do away with the wait condition. And also try increasing the wait time to around 50 seconds to see if you still get the time out exception.

Also I would want to check the xpath- if the exception still persists. Try using any other locater (like CSS Selector) or a different element to wait for to see if the wait condition is working correctly.

Answer 3

Just you are traversing through all the window handles using a for loop. First print the parent window handle.

System.out.println(w1.getWindowHandle());

Take all window handles use toArray() to convert to Object[] a array.

Object[] a=w1.getWindowHandles().toArray();

Then print the window handles of all the windows opened using for loop.

for(int i=0;i<a.length;i++)
{
    System.out.println(a[i]);
}

Now identify in which order windows are printed. (It will be in such an order, that the latest window opened will be at last index of the array elements).

Just get the web element at last index of the array a to switch to it.

String latestWindow=(String) a[a.length-1];//Typea casting from Object type to String is required
w1.switchTo().window(latestWindow);

Now, you can do whatever the things you would like to do on the new window you switched to.