What is the use of plus "+" symbol in code?
Eg: (char) (myRandom.nextInt(26) **+** 'A')
asked Oct 16, 2017 at 8:26
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2 Answers
In this case, the + is moving to the next char in the alphabet from where you are.
The random part doesn't help explain, so this snippet may help.
char x = (char)(1 + 'A'); // returns B. Pos 1 + A (1) gives 2 => B
x = (char)(2 + 'A'); // returns C. Pos 2 + A (1) gives 3 => C
x = (char)(3 + 'A'); // returns D. Pos 3 + A (1) gives 6 => D
x = (char)(1 + 'A'); // returns B. Pos 1 + A (1) gives 2 => B
x = (char)(2 + 'B'); // returns D. Pos 2 + B (2) gives 4 => D
x = (char)(3 + 'C'); // returns F. Pos 3 + C (3) gives 6 => F
Your random statement is seeded with 26. So nextInt(26) will return a random number between 0 and 26. Whatever is returned by that is that moved on one position by the + 'A' part.
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There is a mistake in your comments to the code. 'A' is not coded with 1, otherwise you would not need to use 1+'A', you would just use 2. The sense of using "number+'A'" is that you are not aware of what number "A" is encoded with. So "1+A" will not give you 2. Oct 16, 2017 at 9:16
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Hi, you've take 'gives' too literally. I was just showing how (1+'A') would return 'B'. Oct 16, 2017 at 9:19
This particular line means that you take a random shift from 'A'. Say if
myRandom.nextInt(26) == 1
then you will get 'B'
