How do i find the last element in dynamic list with images that all have the same id is there a function that i can use like


in python, I want to select the last image in a table that have images with the same name

  • do you know what should be the number of the elements in the list?
    – Alexey R.
    Mar 29 '18 at 9:52
  • No as this changes dynamically as rows are added Mar 29 '18 at 10:09
  • Then there is no way to get the last one. If you do not know what element should be the last one, how would Selenium know that?
    – Alexey R.
    Mar 29 '18 at 10:09
  • I was wondering if there was a function similar to last() on c# which finds the last element with the matching id Mar 29 '18 at 10:14
  • I have been able to find the number of the element by using the following Mar 29 '18 at 13:02

The selenium method driver.find_elements_by_id() (note the plural form) returns a list of elements - even if there is a single one.
The idiomatic way of accessing list members is to use [] - [0] will return the 1st, [1] the 2nd, and so on; now, python also supports negative indices in the access - what they mean is "start from the back".

So for a list variable lst, accessing lst[-1] will get you the last element, lst[-2] the second to last, and so on.

In your particular case, this would be the usage:


In languages that do not support negative indices, one would get the length of the list, and access the element at that position minus one (in most languages the list/arrays are zero based, e.g. the first element is at position 0). In python that would be:

elements = driver.find_elements_by_id('editwebsite')
size = len(elements)
target_element = elements[size -1]

, but in python that's not necessary (and some might consider it bad style, "unpythonic")

  • 1
    Thanks for all the help, this is the line of code i will use driver.find_elements_by_xpath('//*[@id="editWebsite"]')[-1].click() Apr 3 '18 at 13:15

At first find all the images with the id. Then select the last image from the list. In python that code would be:

def get_last_image():
    img_list = driver.find_elements_by_id('editwebsite')
    return img_list[len(img_list)-1]

Note: list starts from zero in python. So the last element of list will be at length-1.

Important: Since your images is loading dynamically, to get the last image you should call get_last_image() every time. By doing that you can get the last image from updated image list every time.

  • 1
    Don't use list for a variable name - that's a language keyword you now override, and can't access any more (list() is an object constructor, to return, well, lists :) ) Mar 31 '18 at 8:42

Find a commonality in all the elements... and Get all the elements using xpath.

List<WebElement> image_list = driver.findElements(...);

This returns a list of webElements. You can get the last elemement by

WebElement last_element = image_list.get(image_list.size());

Now you can take control of the last_element. This will also take care of the dynamically loaded images. Hope this helps.

  • image_list.get(image_list.size()) will fail with an IndexOutOfBoundsException. List indexing in Java ranges between 0 and list.size() - 1.
    – hoefling
    Mar 31 '18 at 9:19

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