I have the following code snippet

<div class="space-10"></div>
<form action="/book/index" method="post" class="form-inline" >
<div class="row no-margin no-padding">
<div class="form-group col-sm-3 col-xs-12 no-margin-padding">
   <select id="sport" name="sport" data-style="form-control">
      <option value="">Välj sport</option>
      <option value="1" 
         data-content="<i class='ma ma-Tennis'></i> Tennis">Tennis</option>
      <option value="2" 
         data-content="<i class='ma ma-Badminton'></i> Badminton">Badminton</option>
      <option value="3" 
         data-content="<i class='ma ma-Squash'></i> Squash">Squash</option>
      <option value="4" 
         data-content="<i class='ma ma-Bordtennis'></i> Bordtennis">Bordtennis</option>
      <option value="5" 
         data-content="<i class='ma ma-Padel'></i> Padel">Padel</option>
      <option value="6" 
         data-content="<i class='ma ma-Övrigt'></i> Övrigt">Övrigt</option>
      <option value="7" 
         data-content="<i class='ma ma-Pickleball'></i> Pickleball">Pickleball</option>

And i want random selection of an item from list. I've tried all possible selectors but getting element not found error.

  • You can use Select class with value (write API to generate random number from 1 to 7). This should ideally address your requirement. Could you please share what selectors you have tried. Aug 21, 2018 at 6:10

1 Answer 1


I hope my below code may help you:

Select dropdown = new Select(driver.findElement(By.id("id")));

//Get all options
List<WebElement> dd = dropdown.getOptions();
int index = 0;//if list contains only one element it will take that element
   //Get a random number between 1, size of dd
    random rand = new Random();
    index = rand.nextInt(dd.size()-1);
 }else if(dd.size()<1){
    //print error message
     int = -1;
 if (index >= 0){
  • 1
    Your code misses some checks for dd.size() since if dd.size()-1 would be <=0 you will get an Exception in nextInt()
    – Alexey R.
    Aug 21, 2018 at 8:24
  • my intention is to give an idea of selecting random option, they need to take care of exceptions
    – Nagasatish
    Aug 21, 2018 at 12:22
  • 1
    Of course it is up to you how to give the answer. I'm just saying that your code will not work for size = 1 and it won't take much time to fix.
    – Alexey R.
    Aug 21, 2018 at 13:08
  • it will work for size = 1 , it will take the 0th index element when size is 1
    – Nagasatish
    Aug 22, 2018 at 4:37
  • 1
    No, it will not. Have you ever tried to call new Random().nextInt(0)? Check this: docs.oracle.com/javase/8/docs/api/java/util/…
    – Alexey R.
    Aug 22, 2018 at 8:13

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