What error does this line return when I pass a URL without HTTPS or HTTP
driver.get("www.google.com");
It was asked to a fresher in his interview.
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1Have you tried this statement in your script? – Himanil Gupta Nov 12 at 7:08
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1I do not see any value in this, OP wants others to run a piece of code for him and paste the error. – Moro Nov 13 at 12:03
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I think it is a stupid question to ask in an interview, because it asks a very specific detail of how to use WebDriver that I have not really thought about in the 10 years I am using Selenium, but this might a great answer:
- I don't know, but I could try and see what happens. Why do you ask? Did you have problems with this in the past?
I have just tried removing HTTPS with WebDriver C#, but it uses driver.Navigate().GoToUrl(), it gives:
Message: OpenQA.Selenium.WebDriverException : invalid argument
(Session info: chrome=77.0.3865.120)
I think it might be different depending on language and or browser driver implementation.
There might be a risk that leaving out the HTTPS it could default to HTTP, thus not testing the HTTPS version of the site. I do think HTTP should always redirect to HTTPS and you should only test one version.
answered Nov 12 at 8:47
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Besides the browser itself, there are extensions and configurations to always for HTTPS. The answer is very contextual. – João Farias Nov 12 at 8:53
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You already tried to explain an answer to this question (which shows why the question is not stupid!) – masood ghz Nov 12 at 9:47
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@masoodghz Maybe, I have updated my answer to explain why I think it is a stupid question :) – Niels van Reijmersdal Nov 12 at 10:56
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This question is about WebDriver W3C specification. As per the specification any implementation has to follow:
If url is not an absolute URL or is not an absolute URL with fragment or not a local scheme, return error with error code invalid argument.
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If you try to open a URL without http or https (for e.g. driver.get(“www.facebook.com”);), get() method will throw an error “org.openqa.selenium.WebDriverException“.
It will also gives error message as “Cannot navigate to invalid URL”.
