0

Below is my Selenium Webdriver script. When I run this script my website is opened but the popup window is also opened. How do I close this popup window so the script can continue? Take a look on screenshot also.

package com.angara;

import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.firefox.FirefoxDriver;

public class TestAngaraWeb {

   public static void main(String[]args){

      WebDriver driver = new FirefoxDriver();
      driver.get("http://www.angara.com");
      driver.findElement(By.xpath("/html/body/div[6]/div/div[2]/div/div/div/ul/li/a")).click();


   }
}

enter image description here

  • 1
    I can see no screenshot – dzieciou Dec 7 '12 at 12:03
  • I attached a screenshot (it's a public website). As you can see from the screenshot, this is not a new browser window. – user246 Dec 7 '12 at 15:05
  • 3
    I think the solution is a simple as locating the "X" at the top of that "window" and clicking it. – user246 Dec 7 '12 at 15:08
  • 1
    Knowing common terminology for browser windows can help you in the future. Popup generally refers to a completely new browser window and is what people will assume if you use that term. This is an inline add or popover within your existing web page. – Sam Woods Dec 8 '12 at 2:56
4

As user246 commented, you can write a method to locate the 'X' on the popup and click it if found. Then you can define a custom method to locate an element on the page, something like this (kind of pseudo code):

myFindElement(String xpath)
{
    try{
        driver.findElement(By.xpath(path))
    }
    catch (ElementNotFoundException e){
        if !closethepopup(){print ('Element not found')}
    }
    catch (GeneralException ge){
    }
}

Within your closethepopup() method, you can choose to add some logic to return false if the popup is not found

3

Try this :

Driver.SwitchTo().frame("Fancybox-frame");

Driver.findElement("enter your xpath to close popup").click();

Driver.SwitchTo().defaultContent();
2
  • To close popup- first you need to check which one is the active window in your application (Popup or main window).

  • If popup is active then you can use driver.close(); OR

  • If the main window is active (Focused), then you need to use window handler to close this popup.

0
WebDriver driver = new FirefoxDriver();
driver.get("http://www.angara.com/");
driver.findElement(By.xpath("//*[@id='popsubform']/a/img")).click();

Try this out... hope this will help you out..

0

You can refer this code to close a pop window by clicking on [X].

driver.findElement(By.xpath("//*[@class='_2AkmmA _29YdH8']")).click();

change this thing as per your use @class

0
  driver.findElement(By.xpath("//*[@id="popsubform"]/a/img")).click();

This should look for the "X" on the pop up and close it.

0
System.setProperty("webdriver.gecko.driver", "D:\\all\\geckodriver.exe");

WebDriver driver=new FirefoxDriver();

driver.get("https://www.angara.com/");
Thread.sleep(5000);

for (String winhandle: driver.getWindowHandles()) {
    driver.switchTo().window(winhandle);
    System.out.println("Window Switch");        
    Thread.sleep(2000);

    driver.findElement(By.xpath("(//button[span[contains(text(),'Close')]])[1]")).click();
}

Try this out, this should help you out.

  • Could you please add some details about the code, what is it doing and how could it help the OP? Thanks. – alecxe Feb 28 '18 at 18:57

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