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I got stuck to write the code in WebDriver. I have the code below :

<button class="btn" onclick="javascript:return PopulateInvestor('hdnInvestorId', 'txtInvestorName', 'txtInvestorEmail', '', '', '', '', '',false,'hdnInvestorName','hdnInvestorEmail');">Select</button>

For this I wrote the following:

JavascriptExecutor jse = (JavascriptExecutor)driver;        
jse.executeScript("document.getElement(By.xpath(\"//div[@class='modal-footer']/button[@onclick'return javascript:return PopulateInvestor('hdnInvestorId', 'txtInvestorName', 'txtInvestorEmail', '', '', '', '', '',false,'hdnInvestorName','hdnInvestorEmail');']\").click()");

But still it could not identify element and could not click the button. I can see there is select button present at the end of the code but don't know how to use it. Please advise for this.

  • Is it necessary to find and click the element via JavascriptExecuter? – Twaldigas Oct 8 '14 at 9:35
  • i executed using javascriptExecuter just for check in bcuz it has javascript embedded with the code so i thought of using same for the above code .Please guide me in this case – Ranjan Gupta Oct 8 '14 at 9:55
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This should work:

WebElement element = driver.findElement(By.xpath("//button[@class='btn' and contains(@onclick,'PopulateInvestor')]"));
element.click();

The driver search for the element on this way

  • element has attribute class and the value of this is btn
  • element has attribute onclick and the value of this contains the string PopulateInvestor

Maybe the first point is not necessary to identify the element, but I do not know the whole HTML code.

  • thanx a lot Twaldigas for the solution it worked :) – Ranjan Gupta Oct 8 '14 at 19:54
  • @RanjanGupta Glad to hear. Please accept this answer, so every visitor can easily see that this works. – Twaldigas Oct 9 '14 at 6:59
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Try this line of code:

Driver.findElement(By.xpath("enter your xpath")).click();

Hope it works out!

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