New answers tagged python
0
This can be done with extra filtering in Python, but the usual straightforward way is to add an extra condition to your CSS selector:
all_items = driver.find_elements_by_css_selector("ul > li")
versus:
filtered_items = driver.find_elements_by_css_selector("ul > li.myclass")
where . is a class selector.
0
Python has a feature called List Compreenshion, aimed at creating lists from other lists, after applying some processing on each element.
1 - Find the li elements:
li_items = driver.find_elements_by_class_name("li")
2 - Filter in only element with a given class:
li_items_with_class = [ item for item in list_items if "my_class" in item.get_attribute("...
0
I don't know the exact answer but maybe can help find the solution. Have you tried finding out if this is actually the correct window handle? You could try debugging by:
Counting the number of window handles
Opening the last window handle in stead of exactly [1]
Reading the DOM of all window handles to see what is found by executing this script over each ...
0
Did you try to read the documetation for the Selenium Python package? See: https://selenium-python.readthedocs.io/navigating.html
Code example from the documentation:
from selenium.webdriver.support.ui import Select
select = Select(driver.find_element_by_name('name'))
select.select_by_index(index)
select.select_by_visible_text("text")
select....
0
The idea here is to apply the findAll - filter - extract pattern.
Find all:
ng_scopes = driver.find_elements_by_class("ng-scope")
Filter:
ng_scopes_with_status_one = [ng_scope for ng_scope in ng_scopes if ng_scopes.find_element_by_css_selector(".col-xs-8 span").text == "1"]
Extract:
ng-repeat_value = ng_scopes_with_status_one[0].get_attribute("ng-...
2
There is an animation when you land the page.
Before using the element, you have to wait for it to be clickable.
element = WebDriverWait(driver, 20).until(
EC.presence_of_element_located((By.ID, "departure")))
2
I don't think you need to iterate through them.
Just target the correct element, your xpath could look like this:
//li[@data-cy='roundTrip']
One of the problems with your current xpath is you're trying to find an 'a' element, where the fake radio buttons are actually 'li' elements.
2
You first have to open the menu, by clicking on the From City text, using ID.
driver.find_element_by_id("fromCity").click()
Then you can query the autocomplete, but fixing the locator you used (only one class is necessary):
driver.find_element_by_css_selector(".react-autosuggest__input--open")
1
I think by class name only takes a single class not multiple.
You could try a css selector to find elements with two classes:
element = driver.find_element_by_css_selector(".react-autosuggest__input.react-autosuggest__input--open")
Or just only use one of the classes instead of both.
0
You should try looping over the list you created. z is a list, and when you don't loop over the list it tries to run only once.
for value in z:
driver.find_element_by_xpath("//div[text()='Maximum 5000 Names']/..//textarea").send_keys(value)
time.sleep(2)
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