(I am a bit of a StackOverflow newbie, so please forgive any beginner mistakes and let me know what to improve in the future)

I am trying to select the highlighted button in the appended picture.


  • There are many buttons of this kind all using the same description and XPath. So as far as I can tell there is no way of telling them apart by their cssSelector or XPath

Possible solution:

  • The h2 above the button contains a differentiable description of the button I need to select. So can I basically navigate to said h2 and then select the specific button belonging to it? -> How to code it? Are there easier ways to do this?

So far I know basic element selection as seen in this code sample:

    WebElement loginElement = driver.findElement(By.xpath("//*[@id='login-submitBtn']"));

html sample

  • welcome to the community. You wrote good first question post here. Keep it up & accept answer which helped you. Happy teting! Commented Jan 25, 2023 at 12:55

1 Answer 1



  • You can use different advance locator strategy using xpath which selenium supports. There would be many but mentioning few below:
  • Option 1: XPath using ‘AND’ & ‘OR’
    • The ‘AND’ & ‘OR’ operators in the XPath selector in Selenium are used when locating a WebElement based on certain condition sets
    • In the case of ‘AND,’ both the conditions should be True
    • On the other hand, either of the two conditions can be true for ‘OR’ in operator XPath
  • Option 2 : Relative locators if you are using Selenium 4

How to implement it?

  • Option 1:
    • Using AND
driver.findElement(By.xpath("//h2[@type='button' AND @name='select-organisation-button']"
  • Using Tag with Class, and Attribute value
  • Option 2:
targetted_button_locator = locate_with(By.TAG_NAME, "h2").below({By.NAME: "select-organisation-button"})

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